package com.linkai.多线程._07_gaoji;


/**
 * @Description: 测试生产者，消费者问题2：信号灯法，标志位法解决
 * @Author: 林凯
 * @Date: 2021/10/20 0:08
 */
public class TestPC2 {
    public static void main(String[] args) {
        TV tv = new TV();
        new Player(tv).start();
        new Watcher(tv).start();
    }
}

// 生产者->演员
class Player extends Thread {
    TV tv;

    public Player(TV tv) {
        this.tv = tv;
    }

    @Override
    public void run() {
        for (int i = 0; i < 20; i++) {
            if (i % 2 == 0) {
                this.tv.play("快乐大本营播放！");
            } else {
                this.tv.play("抖音：记录美好生活");
            }
        }
    }
}

// 消费者->观众
class Watcher extends Thread {
    TV tv;

    public Watcher(TV tv) {
        this.tv = tv;
    }

    @Override
    public void run() {
        for (int i = 0; i < 20; i++) {
            tv.watch();
        }
    }
}

// 产品->节目
class TV {
    // 演员表演，观众
    // 观众观看，演员等待
    String voice;       // 表演的界面
    boolean flag = true;

    // 表演
    public synchronized void play(String voice) {

        if (!flag) {
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }

        System.out.println("演员表演了" + voice);
        this.notifyAll();       // 通知唤醒
        this.voice = voice;
        this.flag = !this.flag;
    }

    // 观看
    public synchronized void watch() {
        if (flag) {
            try {
                this.wait();
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        }
        System.out.println("观看了" + voice);
        // 通知演员表演
        this.notifyAll();
        this.flag = !this.flag;
    }
}
